- Category: Contests
- Published: Saturday, 20 November 2021 12:57
- Written by Lupe R Haas
HOUSE OF GUCCI starring Lady Gaga, Adam Driver, Jaret Leto, Al Pacino, and Salma Hayek is coming to movie theaters this Thanksgiving weekend and CineMovie has Fandango tickets to giveaway. Read on to find out how to enter and win.
Directed by Ridley Scott, House of Gucci is inspired by the shocking true story of the family behind the Italian fashion empire. When Patrizia Reggiani, an outsider from humble beginnings, marries into the Gucci family, her unbridled ambition begins to unravel the family legacy and triggers a reckless spiral of betrayal, decadence, revenge, and ultimately… murder.
Lady Gaga stars as Patrizia Reggiani, wife of Maurizio Gucci played by Adam Driver. Jared Leto also stars as Paolo Gucci along with Al Pacino who stars as Aldo Gucci and Jeremy Irons as Rodolfo Gucci. The film also features Mãdãline Ghenea as Sophia Loren, Salma Hayek as Pina Auriemma, Camille Cottin as Paola Franchi and Jack Huston as Domenico De Sole.
Codes are active and expire on January 31, 2022 at 11:59PM (PST) or when HOUSE OF GUCCI is no longer in any theater. This claim code can be redeemed for up to: 2 free ticket(s) of the highest price in the order. Include service fees for those tickets up to a maximum of $30.00.
DUNE Ticket Giveaway (“Sweepstakes”) begins on or about November 19, 2021 at 6:00 p.m. Eastern Time ("ET") and ends on November 30, 2021 at 11:59 p.m. ET (the “Sweepstakes Period”). At the end of the Sweepstakes Period, a random drawing will be conducted to select winners from among all eligible entries received, as more fully set forth in the OFFICIAL RULES. Entry in the Sweepstakes does not constitute entry into any other promotion, contest or sweepstakes. By participating in the Sweepstakes, each entrant unconditionally accepts and agrees to comply with and abide by these Official Rules and the decisions of CineMovie TV, 2700 Arlington Ave. Ste. 101 Torrance, CA 90501 (“Sponsor”), which shall be final and binding in all respects.